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Dibujar los (temas del Capítulo 4). Localizar el eje neutro de la sección transversal.
: Cálculo de la distribución de cortante horizontal y vertical. Disponibilidad del Solucionario solucionario mecanica de materiales fitzgerald capitulo 5
: Análisis de vigas sometidas únicamente a momentos flectores. Fórmula de la flexión : Uso de la ecuación Dibujar los (temas del Capítulo 4)
: Selección de perfiles adecuados basados en el esfuerzo permisible y el módulo de sección ( El solucionario detalla cómo encontrar los puntos donde
| Mistake | Why it’s wrong | Fix | |---------|----------------|-----| | Using diameter instead of radius in ( \tau = T r / J ) | Formula uses radius (r) to surface | Remember (r = d/2) | | Forgetting (G) for angle of twist | Angle formula has (G) in denominator | Always include (G) | | Mixing degrees and radians | ( \phi ) in radians for formulas | Convert degrees to radians (multiply by (\pi/180)) | | Using (J = \pi d^4/32) for hollow shafts | That’s only for solid | Use ( \pi (d_o^4 - d_i^4)/32 ) |
$\sigma_1,2 = \frac163+02 \pm \sqrt\left(\frac163-02\right)^2 + (122.2)^2$ $= 81.5 \pm \sqrt6642.25 + 14932.84 = 81.5 \pm \sqrt21575.09$ $= 81.5 \pm 146.9$ $\sigma_1 = 228.4$ MPa, $\sigma_2 = -65.4$ MPa.
En el Capítulo 5, la localización del momento máximo es crítica, ya que es donde la viga experimenta los mayores esfuerzos de flexión. El solucionario detalla cómo encontrar los puntos donde la fuerza cortante es cero ($V=0$), ya que ahí es donde el momento flector alcanza su valor máximo
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